WebWhen I try to synthesize the design that instantiates this template I get, for each instantiated FFT stage, the warning: WARNING: [HLS 200-960] Cannot flatten loop 'VITIS_LOOP_12_1' (../src/FFTStage.h:12:44) in function 'FFTStage >, std::complex >, 256, 8, TypeTrait>::run' the outer loop is not a perfect loop. … WebI cannot write break: 'break' and 'continue' are not allowed in 'when' statements. Consider using labels to continue/break from the outer loop. Is it a way to return/break from when statements? Or what is the best way to solve it? kotlin Share Improve this question Follow asked Jan 31, 2024 at 18:13 Feeco 4,854 7 35 68 2
Loop Flattening and Perfect Loops with templates - Xilinx
WebJul 10, 2011 · int points = 0; int goal = 100; while (goal <= 100) { for (int i = 0; i < goal; i++) { if (points > 50) { break; // For loop ends, but the while loop does not } // I know I could put a 'break' statement here and end // the while loop, but I want to do it using just // one 'break' statement. points += i; } } Is there a way to achieve this? WebConvert Nested for -Loops to parfor -Loops. A typical use of nested loops is to step through an array using a one-loop variable to index one dimension, and a nested-loop variable to index another dimension. The basic form is: X = zeros (n,m); for a = 1:n for b = 1:m X (a,b) = fun (a,b) end end. The following code shows a simple example. high water beaumaris
How to Solve Python SyntaxError: ‘break’ outside loop
WebMay 30, 2011 · The best approach I know to continue an outer loop is using a Boolean that is scoped under the outer loop and breaking the inner one. Although, depending on the use case you may not break the inner loop, continuing an outer loop inside its inner loop implicitly suggests that you want to immediately jump to the first line of the outer loop … WebYou can using just a break-n statement: foreach (...) { foreach (...) { if (i.name == j) break 2; //Breaks 2 levels, so breaks outermost foreach } } If you're in php >= 5.3, you can use labels and goto s, similar as in ActionScript: foreach (...) { foreach (...) { if (i.name == j) goto top; } } top: But goto must be used carefully. WebMay 18, 2024 · You cannot break an outer loop from an inner loop as the break -command will always reflect of the innermost loop it is nesting in. For for -loops this behavior is very much intentional, because for loops should (only) be used when you know the scope of iterations and it is fixed. Otherwise the use of while loops is recommended. … high water bell bottoms