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The mean of 50 observations was 36

Splet19. jan. 2024 · The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is___________? Hamad Arithmetic Mcqs Average Mcqs Basic Maths Mcqs 19/01/2024 A. 35.2 B. 36.1 C. 36.5 D. 39.1 Explanation: Correct sum = (36 * 50 + 48 – 23) = 1825. Correct mean = 1825/50 = 36.5 … SpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is? - Quora Answer (1 of 3): 50 observations sum/50=36 50 observation sum=50*36=1800 Then 48 taken wrongly as 23 48–23=25 Then real sum of 50 observation=1800+25=1825 Then 1825/50=36.5

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SpletTo calculate "within 1 standard deviation," you need to subtract 1 standard deviation from the mean, then add 1 standard deviation to the mean. That will give you the range for 68% of the data values. 285− 37 = 248 285 − 37 = 248 285+ 37 = 322 285 + 37 = 322 The range of numbers is 248 to 322. The second part of the empirical rule states ... SpletThen Y ~ N(172.36, 6.34). The mean height of 15 to 18-year-old males from Chile from 2009 to 2010 was 170 cm with a standard deviation of 6.28 cm. Male heights are known to follow a normal distribution. ... 6 = 44 and 50 + 6 = 56 are within one standard deviation of the mean 50. The z-scores are –1 and +1 for 44 and 56, respectively. huggingface bilstm https://letiziamateo.com

The mean of 50 observations was 36. It was found l

SpletTranscribed Image Text: A random sample of n = 36 observations is drawn from a population with a mean equal to 15 and a standard deviation equal to 6. Complete parts a through g below. a. Give the mean and standard deviation of the (repeated) sampling distribution x. x = ox (Type integers or decimals.) SpletThe mean of 50 observations was 36. It was found later that anobservation 48 was wrongly taken as 23. The corrected (new) mean is(1) 35.2 (2) 36.1(3) 36.5 (4... SpletThe mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect … huggingface best text generation

The mean of 50 observations was 36. It was found later that an ...

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The mean of 50 observations was 36

The mean of 50 observations was 36. It was found later …

SpletAccording to the question The mean of 50 no. is = 30 Sum of 50 no. is = 50 × 30 = 1500 later it was discovered that two entries were wrongly entered as 82 and 13 instead of 28 and 31. ∴ Difference = (82 + 13) - (28 + 31) = 95 - 59 = 36 (Extra) ∴ Actual sum of 50 numbers is 1500 - 36 = 1464 ∴ Actual avg. 1464 50 = 29.28 SpletThe mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is : Answer: B) 36.5 Explanation: Correct Sum = (36 …

The mean of 50 observations was 36

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SpletSolutions for The mean of 50 observations was 36. It was found later that an observation 48 was wringly taken as 23. The corrected new mean is:a)35.2b)36.1c)36.5d)39.1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Banking Exams. SpletGiven, the mean of 50 observations = 80.4 ∴ Sum of 50 observations = 80.4 × 50 = 4020 But later, we observed that 96 was misread as 69 at one place. Then, the correct mean = (sum of 50 observations) − 69 + 96 50 = 4020 − 69 + 96 50 = …

SpletArrange data points from smallest to largest and locate the central number. This is the median. If there are 2 numbers in the middle, the median is the average of those 2 numbers. The mode is the number in a data set that occurs most frequently. Count how many times each number occurs in the data set. The mode is the number with the highest tally. SpletThe sum of all the 50 observations = 36 × 50 = 1800. Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 × 36. So, the mean of remaining 48 observations …

SpletThe sum of deviations of n number of observations measured from 2.5 is 50 . The sum of deviations of the same set of observations measured from 3.5 is -50 . What is the value of n ? [NDA-I 2024] SpletThe mean of 50 observations is 39. If one of the observations which was 23 was replaced by 43, the resulting mean will be A 39 B 40.6 C 39.4 D 38 Solution The correct option is B 39.4 We know, Mean = Sum of 50 observations Number of observations ⇒ Sum of 50 observations=Mean×Sum of 50 observations = 39×50 = 1950

SpletQuestion 1: Find the mean of the following data set. 10, 20, 36, 12, 35, 40, 36, 30, 36, 40 Solution: Given, x i = 10, 20, 36, 12, 35, 40, 36, 30, 36, 40 n = 10 Mean = ∑x i /n = (10 + 20 + 36 + 12 + 35 + 40 + 36 + 30 + 36 + 40)/10 = 295/10 = 29.5 Therefore, the mean of the given data set is 29.5.

SpletThe mean of 50 observations was 36.If was found later that one item 48 was wrongly taken as 23. The corrected new mean is a 40 b. 42 C. 35 d. 36.5 This problem has been solved! holiday heating and air lincolnton ncSpletA sample of 36 observations is selected from a normal population. The sample mean is 21, and the population standard deviation is 5. Conduct the following test of hypothesis using the .05 significance level. ... The sample mean is 102. A sample of 50 observations is selected from a second population with a population standard deviation of 6 ... holiday heights elementarySpletFind the probability that the mean of a sample of size 36 will be within 10 units of the population mean, that is, between 118 and 138. ... Find the probability that in a sample of 50 returns requesting a refund, the mean such time will be more than 50 days. Scores on a common final exam in a large enrollment, multiple-section freshman course ... huggingface bookcorpus